Matematika 1.[tex] \sqrt[3]{125} + \sqrt[3]{1728} - \sqrt[3]{8000} [/tex]a. 3b. 27c. -3d. 272. Hasil dari 3 1/5 + 8 3/4 adalah?a. 13 39/40b. 12 38/40c. 11 19/20d. 20tolong dong ​

dejarunolfsdottirulv – June 01, 2023

1.
[tex] \sqrt[3]{125} + \sqrt[3]{1728} - \sqrt[3]{8000} [/tex]
a. 3
b. 27
c. -3
d. 27

2. Hasil dari 3 1/5 + 8 3/4 adalah?
a. 13 39/40
b. 12 38/40
c. 11 19/20
d. 20

tolong dong ​

1. A. -3

2. [tex]\sf C. \:11 \frac{19}{20} [/tex]

Penjelasan dengan langkah-langkah:

[tex]\sf \sqrt[3]{125} + \sqrt[3]{1.728} - \sqrt[3]{8.000} = [/tex]

[tex]\sf = \sqrt[3]{ {5}^{3} } + \sqrt[3]{ {12}^{3} } - \sqrt[3]{ {20}^{3} } [/tex]

[tex]\sf = \sqrt{ {5}^{ \frac{3}{3} } } + \sqrt{ {12}^{ \frac{3}{3} } } - \sqrt{ {20}^{ \frac{3}{3} } } [/tex]

[tex]\sf = \sqrt{ {5}^{1} } + \sqrt{ {12}^{1} } - \sqrt{ {20}^{1} } [/tex]

[tex]\sf = 5 + 12 - 20[/tex]

[tex]\sf = 17 - 20[/tex]

[tex]\sf = - 3[/tex]

[tex] \: [/tex]

[tex]\sf 3 \frac{1}{5} + 8 \frac{3}{4} = [/tex]

[tex]\sf = \frac{(3 \times 5) + 1}{5} + \frac{(8 \times 4) + 3}{4} [/tex]

[tex]\sf = \frac{16}{5} + \frac{35}{4} [/tex]

[tex]\sf = \frac{16 \times 4}{5 \times 4} + \frac{35 \times 5}{4 \times 5} [/tex]

[tex]\sf = \frac{64}{20} + \frac{175}{20} [/tex]

[tex]\sf = \frac{64 + 175}{20} [/tex]

[tex]\sf = \frac{239}{20} [/tex]

[tex]\sf = 11 \frac{19}{20} [/tex]

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